Compare two version numbers version1 and version2. If version1 > version2
return 1;
if version1 < version2
return -1;
otherwise return 0
.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
You may assume the default revision number for each level of a version number to be 0
. For example, version number 3.4
has a revision number of 3
and 4
for its first and second level revision number. Its third and fourth level revision number are both 0
.
Input:version1 = "0.1", version2 = "1.1" Output: -1
Input:version1 = "1.0.1", version2 = "1" Output: 1
Input:version1 = "7.5.2.4", version2 = "7.5.3" Output: -1
Input:version1 = "1.01", version2 = "1.001" Output: 0 Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1”
Input:version1 = "1.0", version2 = "1.0.0" Output: 0 Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"
- Version strings are composed of numeric strings separated by dots
.
and this numeric strings may have leading zeroes. - Version strings do not start or end with dots, and they will not be two consecutive dots.
implSolution{pubfncompare_version(version1:String,version2:String) -> i32{letmut version1 = version1 .split('.').map(|n| n.parse().unwrap()).collect::<Vec<_>>();letmut version2 = version2 .split('.').map(|n| n.parse().unwrap()).collect::<Vec<_>>();whileletSome(&0) = version1.last(){ version1.pop();}whileletSome(&0) = version2.last(){ version2.pop();}match version1.cmp(&version2){ std::cmp::Ordering::Greater => 1, std::cmp::Ordering::Less => -1, std::cmp::Ordering::Equal => 0,}}}